# Python没有原生的switch-case语句，但可以通过以下几种方式来实现类似的功能：

# if-elif-else结构：最直接的方法，适合简单的条件判断
# 字典映射：推荐的方法，利用字典的键值对映射实现高效的条件分支
# 函数字典：在字典中存储函数对象，实现复杂的逻辑处理
# Python 3.10+ match语句：现代Python提供的模式匹配语法


# 字典映射
def switch_dict(case):
    switcher = {
        "A": "case A",
        "B": "case B",
        "C": "case C",
    }
    return switcher.get(case, "Defaule Case")


result = switch_dict("A")
print(result)  # case A
result = switch_dict("D")
print(result)  # Defaule Case


# 使用函数字典
def case_a():
    return "Action for case A"


def case_b():
    return "Action for case B"


def case_c():
    return "Action for case C"


def case_default():
    return "Default action"


def switch_funtion_dice(case):
    switer = {"A": case_a, "B": case_b, "C": case_c}
    fn = switer.get(case, case_default)
    return fn()


result = switch_funtion_dice("A")
print(result)
result = switch_funtion_dice("F")
print(result)


# 自 Python 3.10 起，官方引入了结构化匹配（match 语句），可以原生实现类似 switch 的多分支选择功能。match 让代码更加优雅、可读性更强，尤其适用于分支较多、需要解构或复杂条件匹配的场景。


def switch_match(case):
    """
    使用 Python 3.10+ 的 match 语句实现 switch 功能
    这是最现代和强大的方法
    """
    match case:
        case "A":
            return "Case A"
        case "B":
            return "Case B"
        case "C":
            return "Case C"
        case _:
            return "Default case"


result = switch_match("A")
print(result)
result = switch_match("F")
print(result)  # Default case


# 数值范围匹配
def grade_evaluator(sorce):
    grade_map = {
        range(90, 101): "A",
        range(80, 90): "B",
        range(70, 80): "C",
        range(60, 70): "D",
    }
    for score_range, grade in grade_map.items():
        if sorce in score_range:
            return grade

    return "F"


# 测试成绩评估
scores = [
    {"scorce": 95},
    {"scorce": 85},
    {"scorce": 75},
    {"scorce": 65},
    {"scorce": 55},
]

for item in scores:
    grade = grade_evaluator(item["scorce"])
    item["grade"] = grade

print(scores)


def greet(name, msg="Hello"):
    print(f"{msg}, {name}!")


greet("Alice")  # 输出：Hello, Alice!
greet("Bob", "Hi")  # 输出：Hi, Bob!


num_enough = 10
print(num_enough is False)